Solve $\displaystyle (x^2+1)y' + y^2 + 1 =0, y(3)=2$. Find y in terms of x only. Simplify so that your answer does not contain any trigonometric or inverse trig functions.

$\displaystyle (x^2+1)y' + y^2 + 1 =0, y(3)=2$

$\displaystyle dy/dx + y^2 = -\frac{1}{x^2+1}$

I'm stuck here, how do I get it so I can have y^2 multiplied by dy and have the other side multiplied by dx so I can integrate?