I need to derive the formula above by using the definition of cosh (which I think is below) and then solving for the inverse

How do I get the e^-x and e^x to join to create like 1 variable so I can solve for the inverse?

Printable View

- September 27th 2007, 09:55 AMcircuscircusInverse of cosh

I need to derive the formula above by using the definition of cosh (which I think is below) and then solving for the inverse

How do I get the e^-x and e^x to join to create like 1 variable so I can solve for the inverse? - September 27th 2007, 10:04 AMtopsquark
- September 27th 2007, 10:28 AMKrizalid
Another way to see this

Recall

, where is a constant

Since can be integrated by makin' a substitution defined by , it yields

Since two antiderivatives of a function can differ at most by a constant, there must exist a constant such that

Evaluating this equality for

Therefore