Find the equation of the tangent to the curve y = ln(3x − 2) at the point where x = 1. I differentiated this and got 3/3x-2, whats my next step?
to find the equation of a line tangent to a curve defined by at ...
1. you need the point of tangency on the curve,
2. you need the value of the slope of the curve at the point of tangency ,
3. now that you have a point and a slope, , write the equation in point-slope form ...