Find the equation of the tangent to the curve y = ln(3x − 2) at the point where x = 1. I differentiated this and got 3/3x-2, whats my next step?
1. you need the point of tangency on the curve,
2. you need the value of the slope of the curve at the point of tangency ,
3. now that you have a point and a slope, , write the equation in point-slope form ...