p(x)= x^3 + ax^2 + bx + 6 i know (x-2) is a factor and when divided by (x-1) the remainder is 4, i have done the first part and solved for a and b

a=-4 and b=1

the next step asks me to find the two other linear factors of p(x), i keep thinking quadratics but cant see it, i also tried dividing p(x) into (x-2) to get the quadratic, i get a remainder of 32..... after that im stuck, please tell me if im going good and what to do next.