f(x) = 2x^3 - (cosx)^3, x for all [0, pi]. Show f is one to one and find (f^-1)'(-1). Note (0,-1) for all f. x = 2y^3 - (cosy)^3 Is there a way I can factor the y so there is only one of them?
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On observe that . That means that is increasing there. Moreover, .
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