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Thread: calculus

  1. March 16th 2012, 03:44 AM #1
    prasum
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    calculus

    evaluate integral( log(1+x)/(1+x^2)) here can we use log(1+x) series
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  2. March 16th 2012, 05:26 AM #2
    HallsofIvy
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    Re: calculus

    Okay, what is that series?
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  3. March 17th 2012, 02:43 AM #3
    prasum
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    Re: calculus

    the series is x-x^2/2+x^3/3_x^4/4... infinite
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