the function is y=x+(1/x) at y=17/4 attempt: y^-1: x=y+(1/y) differentiate: 1=y'+ln(y)y' 1=y'(1+ln(y)) y'=1/(1+ln(y)) put that over 1: 1+ln(y) plug in y: 1+ln(17/4) =approximately 2.447
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$\displaystyle \text{If}~ y(x)=x+\frac{1}{x} ~\text{then}~x(y)=\frac{1}{2} \cdot (y \pm \sqrt {y^2-4})$
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