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Math Help - slope of secant line

  1. #1
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    slope of secant line

    Consider function y=f(x)=sqrt of x

    The slope of secant line connecting the points (4,2) and (9,3) is?

    I get m=x2-x1/y2-y1 = 1/5

    Now from that I have to come up with equation of the secant line, and the slope of the tangent line to the curve at point (4,2)... can you guys shed a little light on this? Thanks in advance!
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by boousaf View Post
    Consider function y=f(x)=sqrt of x

    The slope of secant line connecting the points (4,2) and (9,3) is?

    I get m=x2-x1/y2-y1 = 1/5

    Now from that I have to come up with equation of the secant line, and the slope of the tangent line to the curve at point (4,2)... can you guys shed a little light on this? Thanks in advance!
    the equation of a line with slope m through the point (x_1,y_1) is given by the point-slope form:
    y - y_1 = m(x - x_1)

    for the second part of the question, find f'(4), that will give you the slope of the tangent line at x = 4
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