Hi,

I've been working on the following problem- the question is to integrate the following

dx/2xlog^18x.

I have used substitution letting u= log x and therefore du=dx/x. When I integrate I get 1/2[u^-17/-17 + C].Subbing back in for u this gives me 1/2[log^-17x/-17 + C].

We are asked to verify our answer by differentiating and seeing if we get the original function. However, when I differentiate I get 1/2[log^-18x] = 1/2log^18x. As you can see I am missing an x in the denominator.

I would appreciate some help please!! Keep going over it but dont know where I'm going wrong. Thanks