Results 1 to 2 of 2

Thread: Tricky Implicit Differentiation

  1. March 12th 2012, 08:39 AM #1
    charlottewill
    charlottewill is offline
    Newbie
    Joined
    Mar 2012
    From
    Exeter
    Posts
    9

    Unhappy Tricky Implicit Differentiation

    Hi,

    How could I possibly differentiate x = a - 1/(kt-c) where c is an integration factor in order to provide the equation

    dx/dt = k(a-x)(b-x)

    assuming that a = b
    Follow Math Help Forum on Facebook and Google+
  2. March 12th 2012, 02:38 PM #2
    Ridley
    Ridley is offline
    Member
    Joined
    Dec 2011
    Posts
    83
    Thanks
    7

    Re: Tricky Implicit Differentiation

    \frac{dx}{dt}=\frac{k}{(kt-c)^2}=k\left(\frac{1}{kt-c}\right)\left(\frac{1}{kt-c}\right)=k\left(a - a - \frac{-1}{kt-c}\right)\left(a - a - \frac{-1}{kt-c}\right)=k(a-x)(a-x)
    Follow Math Help Forum on Facebook and Google+
« integration: reduction formular! | tricky degree standard differential equation and calculus question! need some advice »

Similar Math Help Forum Discussions

  1. Help with a tricky implicit equation...
    Posted in the Calculus Forum
    Replies: 4
    Last Post: July 10th 2011, 12:38 PM
  2. Implicit differentiation/ partial differentiation
    Posted in the Calculus Forum
    Replies: 2
    Last Post: July 26th 2010, 05:24 PM
  3. Tricky Differentiation
    Posted in the Calculus Forum
    Replies: 3
    Last Post: March 29th 2010, 12:04 PM
  4. Tricky (for me anyway) Differentiation.
    Posted in the Calculus Forum
    Replies: 8
    Last Post: February 8th 2009, 07:00 AM

Search Tags


/mathhelpforum @mathhelpforum