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Math Help - Finishing the equation...am i slow??

  1. #1
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    Finishing the equation...am i slow??

    Hey guys, heres another piece of my problem. I have to make this whole equation A equal to B going in that order. Is my algebra terrible or am I missing something?


    A) M ((√2E /√M)(η)) + K ((√2E /√K)(ξ)) = E


    B) η + ξ = 1

    im at (η)E/M + (ξ )E/K = E

    There is more info and depth to this problem which im not sure if its necessary. But if what I explain is not possible, ill fill in the details.
    Thanks again guys
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by chrsr345 View Post
    Hey guys, heres another piece of my problem. I have to make this whole equation A equal to B going in that order.
    What?

    Just to verify this equation:
    Quote Originally Posted by chrsr345 View Post
    A) M ((√2E /√M)(η)) + K ((√2E /√K)(ξ)) = E
    \frac{1}{2}M \left ( \sqrt{ \frac{2E}{M}} \eta \right ) ^2 + \frac{1}{2}K \left ( \sqrt{ \frac{2E}{K}} \xi \right ) ^2 = E

    Then this equation simplifies to
    \frac{1}{2}M \left ( \frac{2E}{M} \eta ^2 \right ) + \frac{1}{2}K \left (\frac{2E}{K} \xi ^2 \right ) = E

    E \eta ^2 + E \xi ^2 = E

    E( \eta ^2 + \xi ^2 ) = E

    Equation B says that \eta ^2 + \xi ^2 = 1 so the energy equation reads
    E (1) = E

    E = E
    which is an identity.

    Is that what you are trying to do?

    -Dan
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  3. #3
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    thannks so much Dan you are really good. Well you basically nailed it, but what i need to do is fully convert equation A to equation B. Like start with A, and then when im done, it should look like B.

    Last edited by chrsr345; September 26th 2007 at 06:20 PM.
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  4. #4
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    thank you Dan, you awesome I pretty much just had a simple mistake..as usual
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by chrsr345 View Post
    thank you Dan, you awesome I pretty much just had a simple mistake..as usual
    Don't feel bad. Those are the worst kind to correct on your own.

    -Dan
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