Hey guys, im Chris and im new to the forum. Im just getting into the bulk of my ME degree in my sophmore year and things are proving quite difficult.
Anyways, im stuck on the calc 2 problem related to simple harmonic motion.
s(t) = √2E /√K sin ((√K/√M)t + φ)
Find the area trapped between the graph of the function s(t) and the t-axis over one half of the period (one arc of the wave)
the wave between -Q(√M/√K) and (√M/√K)(π – Q)
Heres where im at:
(√2E /√K)(- √M/√K) cos (π – Q) - (√2E /√K)(- √M/√K) cos (– Q)
does it look right? do i need to go further somehow?
If you guys need anymore info, ill be glad to fill in. Thanks so much!
ah thanks about the coefficient. But im confused about the How and why did you solve for pi?
that looks just like what i had for my F(a)- F(b)...
(coeff)cos - (coeff)cos =
(√2E /√K)(- √M/√K) cos (π – Q) - (√2E /√K)(- √M/√K) cos (– Q)
Did i miss something?