use the quotient rule to differentiate the function
k(x)= (e^6x)/(x^3+8)
I have got as far as
k '(x) =(x^3+8)(6e^6x)-(e^6x)(3x^2)/(x^3+8)^2
But im unsure how to take it any further would anyone be able to help us?
use the quotient rule to differentiate the function
k(x)= (e^6x)/(x^3+8)
I have got as far as
k '(x) =(x^3+8)(6e^6x)-(e^6x)(3x^2)/(x^3+8)^2
But im unsure how to take it any further would anyone be able to help us?
What Siron meant is this:
$\displaystyle \frac{dk}{dx} = \frac{3e^{6x}(2x^{3} + 16 - x^{2})}{(x^{3} + 8)^{2}}$
You just factor $\displaystyle 3e^{6x}$ using simple algebra.
You can also find differentiation of $\displaystyle k(x)= \frac{e^{6x}}{x^3+8}$ in the following link:
differentiate (e^(6x))/(x^3+8) - Wolfram|Alpha