Your answer is correct! The only thing you can do is put a factor outside in the numerator.
use the quotient rule to differentiate the function
k(x)= (e^6x)/(x^3+8)
I have got as far as
k '(x) =(x^3+8)(6e^6x)-(e^6x)(3x^2)/(x^3+8)^2
But im unsure how to take it any further would anyone be able to help us?
What Siron meant is this:
You just factor using simple algebra.
You can also find differentiation of in the following link:
differentiate (e^(6x))/(x^3+8) - Wolfram|Alpha