problem:
Integrate (2x-1)/(x+1) from 0 to 3
the first thing I do is pull out the constant 2. Then the part to integrate can become ln(x-1)-ln(x+1)
the antiderivative of ln(x-1) is:
x(ln(x-1)-1)-ln(1-x)
the antiderivative of ln(x+1) is:
(x+1)ln(x+1)-x
x(ln(x-1)-1)-ln(1-x)-(x+1)ln(x+1)-x
3(ln(3-1)-1)-ln(1-3)-(3+1)ln(3+1)-x
I can already tell this answer is wrong due to the fact that I have negatives in the ln
the final answer should be 6(1-ln2)
any help?