Thread: Indefinite Integral

$\displaystyle \displaystyle \int \frac{x}{\sqrt{1-x^2.(x+\sqrt{1-x^2})^8}}dx$

Take a look here:
int x/sqrt(1-x^2(x+sqrt(1-x^2))^8) - Wolfram|Alpha

There seems to be a random dot ( . ) in your equation, indicating a potential typo. Is this supposed to be $\displaystyle \int \frac{x}{\sqrt{(1-x^2)(x + \sqrt{1-x^2})^8}} dx$ or $\displaystyle \int \frac{x}{\sqrt{1-x^2(x + \sqrt{1-x^2})^8}} dx$?