I need help with this proof... Prove that It is actually like ln e^(1/5) but I dont know how to make the 5 small...
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Originally Posted by circuscircus I need help with this proof... Prove that It is actually like ln e^(1/5) but I dont know how to make the 5 small... You mean ln[fifth root of e]. "...small 5 sqrt...." ----------that is fifth root. So, prove ln[e^(1/5)] = 1/5 We will use: ---Log[a^b] = b*Log[a] ---Log(base a)[a] = 1 ln[e^(1/5)] = (1/5)ln[e] = (1/5)*Log(base e)[e] = (1/5)*1 = 1/5
Where does this come from? Log[a^b] = b*Log[a]
Originally Posted by circuscircus Where does this come from? Log[a^b] = b*Log[a] Recall that What does mean? It means where we are doing this "b" times. So Note that it does not matter what base the logarithm is to: and -Dan
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