Thread: Sequences question

Is the solution I posted wrong?

For the last part, using L'Hopital's rule on (1 - xln(2))/2^x gives me -ln(2)/[ln(2) * 2^x] = -1/2^x = 0 (ignoring the limit operators - is operator the right word?).

Is the solution wrong or am I not seeing something?

Any input would be appreciated!
Thanks in advance!

Originally Posted by s3a

Is the solution I posted wrong?

Using L'Hopital's rule on (1 - xln(2))/2^x gives me -ln(2)/[ln(2) * 2^x] = -1/2^x = 0 (ignoring the limit operators - is operator the right word?).

Is the solution wrong or am I not seeing something?

Any input would be appreciated!
Thanks in advance!

We are not megicians... WHAT is the question?!

The question is included with the solution.

Originally Posted by s3a

For the last part, using L'Hopital's rule on (1 - xln(2))/2^x gives me -ln(2)/[ln(2) * 2^x] = -1/2^x = 0 (ignoring the limit operators - is operator the right word?).

You have to compute , an differentiate independently numerator and denominator.


Out of curiosity, I don't understand why the problem uses the function , it is not necessary. For example for (a) for all which implies is increasing and its limit is easily obtained by elemental computations. For (b) , which implies is decreasing etc.