If and . Then find Minimum value of
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Originally Posted by jacks If and . Then find Minimum value of Using the method of Lagrange multipliers, Adding, we get or Case 1: Case 2: or Case 2a: Case 2b: No solutions. -------------------------------------------------- So, the minimum value of is 2.
Last edited by alexmahone; January 7th 2012 at 11:46 AM.
Originally Posted by jacks If and . Then find Minimum value of Switch to polars and substitute from the constraint into the objective then simplify to give a standard 1D unconstrained problem. CB
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