# Math Help - Integration

1. ## Integration

Is this question answered ok or should I have an equation in t?

2. ## Re: Integration

The problem is the fact that you write:
$\left(\frac{v}{2}-\frac{v^2}{2}\right)^{-1}=\frac{2}{v}-\frac{2}{v^2}$
which is incorrect.

You can say that:
$\left(\frac{v}{2}-\frac{v^2}{2}\right)^{-1}=\left(\frac{v-v^2}{2}\right)^{-1}=\frac{2}{v-v^2}$

3. ## Re: Integration

Is this correct now? I noticed there is another way of doing the integral but I have not learnt about arctanh.

4. ## Re: Integration

It looks good now!

You can also apply 'complete the square' to solve $\int \frac{dv}{v^2-v}$

5. ## Re: Integration

Thats what I found. I have made an equation in t from the final equation. v=(1-4e^(t/2))^-1

6. ## Re: Integration

It's correct!