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Math Help - Integration

  1. #1
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    Integration

    Is this question answered ok or should I have an equation in t?
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  2. #2
    MHF Contributor Siron's Avatar
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    Re: Integration

    The problem is the fact that you write:
    \left(\frac{v}{2}-\frac{v^2}{2}\right)^{-1}=\frac{2}{v}-\frac{2}{v^2}
    which is incorrect.

    You can say that:
    \left(\frac{v}{2}-\frac{v^2}{2}\right)^{-1}=\left(\frac{v-v^2}{2}\right)^{-1}=\frac{2}{v-v^2}
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  3. #3
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    Re: Integration

    Is this correct now? I noticed there is another way of doing the integral but I have not learnt about arctanh.
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  4. #4
    MHF Contributor Siron's Avatar
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    Re: Integration

    It looks good now!

    You can also apply 'complete the square' to solve \int \frac{dv}{v^2-v}
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  5. #5
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    Re: Integration

    Thats what I found. I have made an equation in t from the final equation. v=(1-4e^(t/2))^-1
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  6. #6
    MHF Contributor Siron's Avatar
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    Re: Integration

    It's correct!
    Last edited by Siron; January 5th 2012 at 09:35 AM.
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