Hello

If I want to find the gradient at any point on a parabola with an equation of the form:

$\displaystyle y^2 = ax$ , where $\displaystyle a > 0$

Do I use $\displaystyle \dfrac{dy}{dx} = \dfrac{a}{2\sqrt{ax}}$

knowing that when $\displaystyle y > 0, \dfrac {dy}{dx} > 0$ and that when $\displaystyle y < 0, \dfrac {dy}{dx} < 0$ or is there another way? I noticed when I used implicit differentiation I didn't get an $\displaystyle x$ term in the derivative.

Thank you