Thread: Definate integrals (the first way- by definition)

∫[0,2,2-x^2,]

Originally Posted by mathk

∫[0,2,2-x^2,]

Welcome to MHF, mathk!

Do you mean ?

If so, could you perhaps show a little of what you know?
That makes it easier for us to help you.

2-0/n= 2/n

x1 = 2/n
x2=4/n
xi-2i/n

\int_0^2f(2i/n)2/n
how do you draw or write limit and summation?

Use [ tex ] ... [ /tex ] around your formulas to display them mathematically (without the spaces before and after "tex").


To get a summation, write [ tex ]\sum_{i=0}^{\infty} x_i[ /tex ], which shows up like:




To get a limit, write [ tex ]\lim_{n \to \infty} x_i[ /tex ], which shows up like:




Click Reply With Quote to see what I did.