sinh x = 2.75 find cosh x exactly...???
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Originally Posted by helmszee sinh x = 2.75 find cosh x exactly...??? recall that $\displaystyle \cosh^2 x - \sinh^2 x = 1$
Originally Posted by Jhevon recall that $\displaystyle \cosh^2 x - \sinh^2 x = 1$ but mine arn't $\displaystyle cosh^2 or sinh^2$ what do i do with the ^2?
Originally Posted by helmszee but mine arn't $\displaystyle cosh^2 or sinh^2$ what do i do with the ^2? umm, you square the answer you have for sinh(x) plug it into the formula, solve for cosh^2(x) and then square root both sides
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