Hello from Greece , I am very much confused with this exercise.Could anyone solve this ???????? Find the area between the parabola $\displaystyle x=y^2-2y-15$ and the lines$\displaystyle y=2$ and $\displaystyle y=-2$ and $\displaystyle y(x=0)$
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The area is $\displaystyle A=\int_{-2}^2-(y^2-2y-15)\;dy=\ldots$
OMG is it so easy
this scheme is it the right one ?
Originally Posted by kotsos this scheme is it the right one ? Why do you ask? You only have "to turn your neck 90 degrees". The horizontal axis is transformed into the vertical one, and reciprocally.
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