Solution:

y = -2

(-2)^2 = x

x = 4

y^2 = +- 2

the point of intersection should be (0,0) and (4,2)

now im using the cylindrical method in obtaining the volume

where dA = (y2-y1)dx

for

y2 = sqrt(x)

y1 = x

and

radius be r = x+2 since the revolved line is at the 2nd quadrant and x in the 1st quadrant and it needs to be added

V = -(416/15)pi ????