I can't figure out how to do this problem. Find the interval(s) where f(x)=sqrt(x-8), x<-4 3x-2, x>or equal to -4 is continuous.
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Originally Posted by ryandman89 I can't figure out how to do this problem. Find the interval(s) where f(x)=sqrt(x-8), x<-4 3x-2, x>or equal to -4 is continuous. How can $\displaystyle \sqrt{x-8}$ make sense for $\displaystyle x<-4$?
thats what I was thinking, but I eventually figured it out. Basically you just ignore that piece and find the range of the other one...really simple.
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