So z^6 = 1 + i*sqrt(3)
Can you write the right side in polar/trig form?
z^6 = 2[cos(60) + i*sin(60)]
The answers that im getting feels like not correct.
z=10^1/12(cos(2npi+1.25/6)+i sin (2npi+1.25/6)) I used this to get values for each z power, and this is what i calculated;
z= 1.4 rads, z1= 1.5rads, z2=0.1rads, z3=1.5rads, z4=-1.5rads, z5=-0.1rads
I believe I should be getting hexagon shape when i plot these numbers on an argand diagram but i wont be able to as some of my calculation are wrong since all sides of hexagon should be equal. Could you pls help me find where im making the mistake.
That means that if you find one of the sixth roots, you can find the others by adding to the angle of the first.
Note, you should really only list those angles that are within the range .