Show that dy/dx is +ve when a < x < b
I have a differentiation problem which starts with
I have to find dy/dx. No problem there, get
Then to find values of x where dy/dy = 0
But then it asks "Denoting the values of x which you have just calculated by a and b, where a < b, show dy/dx is positive when a < x < b".
I can see graphically where dy/dx is positive, but do I need to show algebraically? How would I answer this?
Re: Show that dy/dx is +ve when a < x < b
You want to find where
Originally Posted by angypangy
So the derivative is positive in between these values.