I wish to integrate (4t-2)*e^(t^2-t). U=4t-2 du/dt = 4 dv=e^(t^2-t) dv/dt = ? Am I even on the right track?
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We have: $\displaystyle \int (4t-2)e^{t^2-t}dt$ which we can write as: $\displaystyle 2\int (2t-1)e^{t^2-t}dt$ Now, let $\displaystyle t^2-t=u$ (Do you see why this is a good substitution?)
What is the derivative of $\displaystyle t^{2}-t$?... is it somewhere in the integrand function?... Marry Christmas from Serbia $\displaystyle \chi$ $\displaystyle \sigma$
int t^2-t = 2t-1 Do I then use Integration by parts with dv = ?
No, you don't need integration by parts. Have you done substitutions (in integration) before? Let $\displaystyle t^2-t=u \Rightarrow (2t-1)dt=du$ Do you see how you can use this?
Thank you people - got it - U substitution. 2 int (2t-1)*e^(t^2-t) dt = 2 int e^u du = 2*e^u + c = 2*e^(t^2-t) + c
Yes, that's correct.
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