Integrate 4 + 2x(1+x^2)^3 dx from x=0 to 1
I tried u substitution with u = 1 + x^2 and du = 2x dx and got 7.75, but the answer in the back of the book says 19. What did I do wrong?
Your answer is correct.
http://www.wolframalpha.com/input/?i...dx+from+0+to+1
Your answer is correct.
integrate 4+2x(1+x^2)^3dx from 0 to 1 - Wolfram|Alpha