Integrate 4 + 2x(1+x^2)^3 dx from x=0 to 1

I tried u substitution with u = 1 + x^2 and du = 2x dx and got 7.75, but the answer in the back of the book says 19. What did I do wrong?

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- Dec 14th 2011, 02:05 PMRstewartU substitution with integral
Integrate 4 + 2x(1+x^2)^3 dx from x=0 to 1

I tried u substitution with u = 1 + x^2 and du = 2x dx and got 7.75, but the answer in the back of the book says 19. What did I do wrong? - Dec 14th 2011, 02:13 PMSironRe: U substitution with integral
Your answer is correct.

http://www.wolframalpha.com/input/?i...dx+from+0+to+1 - Dec 14th 2011, 02:15 PMSironRe: U substitution with integral
Your answer is correct.

integrate 4+2x(1+x^2)^3dx from 0 to 1 - Wolfram|Alpha - Dec 14th 2011, 04:20 PMProve ItRe: U substitution with integral