Hello,
I am trying to create a summation equation from this algebra equation, would it be possible?
x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x
If so can anyone help me?
Printable View
Hello,
I am trying to create a summation equation from this algebra equation, would it be possible?
x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x
If so can anyone help me?
Strictly speaking, this is not an equation because it lacks the = sign. It's an expression. If by "summation equation" you mean an expression that uses thesymbol, then
If you want to simplify that expression, then you can use the formula for the sum of an arithmetic progression:
Thank you for the response, I understand that in order to create the equation that symbol is needed but my question is would it be possible to convert the equation I posted into that summation? if so how?
basically it works by set periods for example if the period is set to 3 then the equation would be: x+2x+3x and if the period is set to 4 then the equation would be x+2x+3x+4x
Edit: If this is not what you want, please explain what you mean by "that summation."
Hello,
Yes I needed a formula and that one is good. I guess I was thinking that the formula could have been written using the summation symbol?
The formula with the summation symbol is given in post #2 (you can replace 11 withand add ... in the left-hand side).
I haven't dealt with calculus in a while, thank you very much.
Hello,
I wanted to ask if I got these written correctly:
900: 1x+2x+3x+4x+5x+6x+6x+6x+6x+6x+6x+6x
500: 1x+2x+3x+4x+5x+6x+7x+8x+8x+8x+8x+8x
100: 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x
For these would the equation be correct written:
900: S (upper: 5 lower: 1) ix + S (upper:6 lower: 1) 6x where x = 10000
500: S (upper: 5 lower: 7) ix + S (upper:5 lower: 1) 6x where x = 10000
500: S (upper: 12 lower: 1) ix where x = 10000
I don't see the relationship between 900, 500, 100 and the expressions after the colon.
In this forum, you can write [tex]\sum_{i=1}^{12} ix[/tex] to get.
Below(capital Greek sigma) we typically write
, not just 1, but above
we write just 12 (for example). The notation
means the sum where
ranges from 1 to 12.
Quote:
500: S (upper: 12 lower: 1) ix where x = 10000
is indeed 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x regardless of the value of x.
Quote:
500: S (upper: 5 lower: 7) ix + S (upper:5 lower: 1) 6x where x = 10000
. To represent 8x+8x+8x+8x+8x you can write
, or
(note that there is no
after
, which means that all terms in the sum are the same), or just
.
The 500, 900 is labeling. but are the calculations correct?
No.
In the explicit sum, 6x occurs 7 times, but in the sigma-expression, it is used only 6 times.
It is not clear what 6x is doing in the sigma-expression and why you have, where the upper limit is less than the lower one.
so would it be correct:
?
This is not an equation (it does not have an = sign), so I can't say if it's true or false.
ok is this statement true?
+
= 680000
. However, in post #8 the expression labeled 500 has
=
, which is indeed 680000 for x = 10000.