# differentiability and continuity problem

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• Dec 13th 2011, 08:35 AM
maoro
differentiability and continuity problem
#1 Suppose that the differentiable function $\displaystyle f(x)$ satisfies $\displaystyle f(1)=2$ and $\displaystyle f'(x) \leq 1$. How large can $\displaystyle f(3)$ possibly be?(Done)
If $\displaystyle f(3)=4$, then show that $\displaystyle f(x)=x+1$ for $\displaystyle 1 \leq x \leq 3$.

How to approach this?

#2 Assume $\displaystyle f(x)$ is continuous on $\displaystyle [a,b]$, and for any $\displaystyle x\in[a,b]$, there exists y\in[a,b] such that $\displaystyle |f(y)| \leq \frac{1}{2}|f(x)|$. Prove that there exists a point $\displaystyle c \in [a,b]$ such that $\displaystyle f(c)=0.$
• Dec 13th 2011, 08:51 AM
FernandoRevilla
Re: differentiability and continuity problem
Quote:

Originally Posted by maoro
#1 Suppose that the differentiable function $\displaystyle f(x)$ satisfies $\displaystyle f(1)=2$ and $\displaystyle f'(x) \leq 1$. How large can $\displaystyle f(3)$ possibly be?(Done)
If $\displaystyle f(3)=4$, then show that $\displaystyle f(x)=x+1$ for $\displaystyle 1 \leq x \leq 3$.

Using the Lagrange Theorem for $\displaystyle f$ on $\displaystyle [1,3]$ we have $\displaystyle f(3)=2f'(\xi)+f(1)$ for some $\displaystyle \xi\in(1,3)$ . If $\displaystyle f(1)=2$ , as $\displaystyle f'(\xi)\leq 1$ we conclude $\displaystyle f(3)\leq 4$ . If $\displaystyle f(3)=4$ then $\displaystyle f'(\xi)=1$ so ... (conclude)
• Dec 13th 2011, 08:58 AM
maoro
Re: differentiability and continuity problem
I have just learned about Mean Value Theorem, is it similar to Lagrange Theorem?
btw, if $\displaystyle f(3)=4$, we can just show that $\displaystyle f'(\xi)=1$, but not $\displaystyle f(x)=x+1$
• Dec 13th 2011, 08:59 AM
FernandoRevilla
Re: differentiability and continuity problem
Quote:

Originally Posted by maoro
#2 Assume $\displaystyle f(x)$ is continuous on $\displaystyle [a,b]$, and for any $\displaystyle x\in[a,b]$, there exists y\in[a,b] such that $\displaystyle |f(y)| \leq \frac{1}{2}|f(x)|$. Prove that there exists a point $\displaystyle c \in [a,b]$ such that $\displaystyle f(c)=0.$

Hint: $\displaystyle g(x)=|h(x)|$ is continuous on $\displaystyle [a,b]$ .
• Dec 13th 2011, 09:06 AM
FernandoRevilla
Re: differentiability and continuity problem
Quote:

Originally Posted by maoro
I have just learned about Mean Value Theorem, is it similar to Lagrange Theorem?

Yes, it is another name.

Quote:

btw, if $\displaystyle f(3)=4$, we can just show that $\displaystyle f'(\xi)=1$, but not $\displaystyle f(x)=x+1$
You can prove that $\displaystyle f'(x)=1$ for all $\displaystyle x\in (1,3)$ so $\displaystyle f(x)=x+C$ in $\displaystyle (1,3)$ etc ...
• Dec 13th 2011, 09:09 AM
maoro
Re: differentiability and continuity problem
Quote:

Originally Posted by FernandoRevilla
Yes, it is another name.

You can prove that $\displaystyle f'(x)=1$ for all $\displaystyle x\in (1,3)$ so $\displaystyle f(x)=x+C$ in $\displaystyle (1,3)$ etc ...

Is it because $\displaystyle f$ is differentiable, then if $\displaystyle f'(x)=1$, we get $\displaystyle f(x)=x+C$ ?
• Dec 13th 2011, 09:22 AM
FernandoRevilla
Re: differentiability and continuity problem
Quote:

Originally Posted by maoro
Is it because $\displaystyle f$ is differentiable, then if $\displaystyle f'(x)=1$, we get $\displaystyle f(x)=x+C$ ?

Right.
• Dec 13th 2011, 09:25 AM
maoro
Re: differentiability and continuity problem
Quote:

Originally Posted by FernandoRevilla
Hint: $\displaystyle g(x)=|h(x)|$ is continuous on $\displaystyle [a,b]$ .

What's the next step when $\displaystyle |f(x)|$ is continuous on $\displaystyle [a,b]$ ?
Can i simply state that there exists $\displaystyle c\in [a,b]$ such that

$\displaystyle |f(c)|\leq \frac{1}{2}|f(x_1)|\leq \frac{1}{2^2}|f(x_2)|\leq...\leq\frac{1}{2^n}|f(x_ n)|$
• Dec 13th 2011, 10:04 AM
FernandoRevilla
Re: differentiability and continuity problem
Quote:

Originally Posted by maoro
$\displaystyle |f(c)|\leq \frac{1}{2}|f(x_1)|\leq \frac{1}{2^2}|f(x_2)|\leq...\leq\frac{1}{2^n}|f(x_ n)|$

You have to prove that $\displaystyle c$ exists, so don't start with it. Construct a sequence $\displaystyle (y_n)$ in $\displaystyle [a,b]$ such that $\displaystyle 0\leq g(y_n)\leq 2^{-n}g(a)$ , so $\displaystyle \lim_{n\to +\infty}g(y_n)=0$ etc.
• Dec 13th 2011, 08:02 PM
maoro
Re: differentiability and continuity problem
I saw another problem which is similar to #1
Suppose that $\displaystyle f(x)=0$ and $\displaystyle f'(x) \leq 1$. How large can $\displaystyle f(4)$ possibly be? (Done)
If $\displaystyle f(4) =4$, then show that $\displaystyle f(x)=x$ for $\displaystyle 0 \leq x \leq 4$

The question i want to ask is how can i prove $\displaystyle f(x)=x$ if i don't know $\displaystyle f$ is differentiable ?
• Dec 13th 2011, 10:06 PM
FernandoRevilla
Re: differentiability and continuity problem
Quote:

Originally Posted by maoro
The question i want to ask is how can i prove $\displaystyle f(x)=x$ if i don't know $\displaystyle f$ is differentiable ?

You can't, there are infinite functions satisfying $\displaystyle f(0)=0$ and $\displaystyle f(4)=4$ .