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Math Help - Limits using L'Hopital's Rule

  1. #1
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    Limits using L'Hopital's Rule

    I am getting 0 for the limit below but WolframAlpha says its -0.5. Really confused.


    limit as x goes to 0+ of [ln(x^2+x)-ln(x)-x]/x^2
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  2. #2
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    Oct 2011
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    Re: Limits using L'Hopital's Rule

    stupid mistake, got it...
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