Originally Posted by

**dttah** Hello everyone.

I am not sure how to solve this with Taylor/Mc-Laurin series:

$\displaystyle \frac{\log(e^x-x-x^2)}{log\sin x-\log x}$

I have no problems at the numerator, I mean, I could do Mc-Laurin series for e^x so then I'd have a "1" which could help out in the following Mc-Laurin development:

log(1+x).

I can't help myself at the denominator though. Am I obliged to do Taylor series with center in 1?

And if I do, should I change the others too?

I was thinking even about applying log's properties, but that doesn't bring me too far.

Any suggestions?