# Thread: Mc-Laurin series of sin^3 sqrt(x).

1. ## Mc-Laurin series of sin^3 sqrt(x).

Hello everyone, I would like to ask a question.

Knowing that:

$sinx = x - \frac{x^3}{6} +o(x^3)$

How do I find..:
$sin^3 \sqrt(x)$

$sin \sqrt(x) = \sqrt(x) - \frac{\sqrt(x^3)}{6}$

Woops... I just realized how it should be done, I just had to do that series cubed.
i can't delete the post, sorry for bothering guys. >.<'

2. ## Re: Mc-Laurin series of sin^3 sqrt(x).

The function $f(x)= \sin \sqrt{x}$ is not analytic in x=0 because its derivative doesn't exist here... the same is for $f^{3}(x)$...

Kind regards

$\chi$ $\sigma$