It has been very clearly mentioned that slope at x=-1 is 2, so you have .
That means .
Solve the following equations to get the value of a,b and c.
f(x) := ax˛ + bx + c
find a, b, c ∈ R so that:
for x=-1 f(x)=0, the slope at this point is 2
and for x=1 f'(x)=0
what i haven't encountered before is the expression, THE SLOPE AT THIS POINT IS 2. Does that mean that i take the derivative of the first equation f(x) and that for x=-1 f'(-1)=2, so -2a+b=2 ??
the other two points are clear to me, a-b+c=0 and 2a+b=0
It has been very clearly mentioned that slope at x=-1 is 2, so you have .
That means .
Solve the following equations to get the value of a,b and c.
I know that but my qeustion was (maybe i didn't make it very clear..) when we know the VALUE of the SLOPE in a certain point X, does it translate to>> derivative f'(x) = value of slope, at that point?? Do i take the derivative to figure this out?