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Thread: acceleration

  1. December 10th 2011, 06:46 AM #1
    Stuck Man
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    acceleration

    I have done the first part. The second appears to require integrating v. Could I have some help?
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  2. December 10th 2011, 06:57 AM #2
    skeeter
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    Re: acceleration

    start by taking the derivative on the far right side w/r to s ...

    \frac{d}{ds}\left(\frac{v^2}{2}\right) = v \cdot \frac{dv}{ds} = \frac{ds}{dt} \cdot \frac{dv}{ds} = \frac{dv}{dt} = a
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  3. December 10th 2011, 07:00 AM #3
    sbhatnagar
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    Re: acceleration

    Note that

    a=a\cdot\frac{ ds}{ds}= {dv \over dt}\cdot\frac{ ds}{ds}={ds \over dt}\cdot\frac{ dv}{ds}=v\left(\frac{dv}{ds} \right)
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