# acceleration

• December 10th 2011, 06:46 AM
Stuck Man
acceleration
I have done the first part. The second appears to require integrating v. Could I have some help?
• December 10th 2011, 06:57 AM
skeeter
Re: acceleration
start by taking the derivative on the far right side w/r to s ...

$\frac{d}{ds}\left(\frac{v^2}{2}\right) = v \cdot \frac{dv}{ds} = \frac{ds}{dt} \cdot \frac{dv}{ds} = \frac{dv}{dt} = a$
• December 10th 2011, 07:00 AM
sbhatnagar
Re: acceleration
Note that

$a=a\cdot\frac{ ds}{ds}= {dv \over dt}\cdot\frac{ ds}{ds}={ds \over dt}\cdot\frac{ dv}{ds}=v\left(\frac{dv}{ds} \right)$