Thread: Is this series convergent?

I couldn't solve this:

Σ k=1 -- infinity, (4k+1)^a / (6k^2 + 3k + 1)^b
for all a, b from Z.

How would you solve this??

Originally Posted by nappysnake

I couldn't solve this:

Σ k=1 -- infinity, (4k+1)^a / (6k^2 + 3k + 1)^b
for all a, b from Z.

How would you solve this??

I would consider using the comparison test.

CB