I couldn't solve this: Σ k=1 -- infinity, (4k+1)^a / (6k^2 + 3k + 1)^b for all a, b from Z. How would you solve this??
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Originally Posted by nappysnake I couldn't solve this: Σ k=1 -- infinity, (4k+1)^a / (6k^2 + 3k + 1)^b for all a, b from Z. How would you solve this?? I would consider using the comparison test. CB
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