Assume f(0)=f'(0)=0, prove there exists a positive constant such that f(x)>o...

Assume that f is a differentiable function such that f(0)=f'(0)=0 and f''(0)>0. Argue that there exists a positive constant a>0 such that f(x)>0 for all x in the interval (0,a). Can anything be concluded about f(x) for negative x's? My teacher hinted at using the Mean value theorem but I can never seem to get MVT problems right.

Re: Assume f(0)=f'(0)=0, prove there exists a positive constant such that f(x)>o...

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**NWeid1** Assume that f is a differentiable function such that f(0)=f'(0)=0 and f''(0)>0. Argue that there exists a positive constant a>0 such that f(x)>0 for all x in the interval (0,a). Can anything be concluded about f(x) for negative x's? My teacher hinted at using the Mean value theorem but I can never seem to get MVT problems right.

The conditions given imply that there is a minimum at the origin. So that means that to the right of the origin, the function must increase, even if just for a little while.

Re: Assume f(0)=f'(0)=0, prove there exists a positive constant such that f(x)>o...

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**NWeid1** Assume that f is a differentiable function such that f(0)=f'(0)=0 and f''(0)>0. Argue that there exists a positive constant a>0 such that f(x)>0 for all x in the interval (0,a).

Use the limit definition of derivative.

We know that exists and is positive.

Therefore, .

From which we get .

Re: Assume f(0)=f'(0)=0, prove there exists a positive constant such that f(x)>o...

Plato: I haven't learned this method :\

Re: Assume f(0)=f'(0)=0, prove there exists a positive constant such that f(x)>o...

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**NWeid1** Plato: I haven't learned this method :\

Are you saying that you never learned the definition of a derivative?

How can you be asked to do such a question then?

Re: Assume f(0)=f'(0)=0, prove there exists a positive constant such that f(x)>o...

Not the formal definition. My teacher said to use mean value theorem