Thread: Locating absolute extrema

Locate the absolute extrema of the function on the closed interval: f(x)= cos PIx on [1/2 , 4/3]



I will be very greatful if someone helped me understand what i must do

Originally Posted by zully32

Locate the absolute extrema of the function on the closed interval: f(x)= cos PIx on [1/2 , 4/3]



I will be very greatful if someone helped me understand what i must do

Global maxima and minima can occur at endpoints or stationary points.

Can you evaluate the function at the endpoints? Can you use calculus to evaluate the stationary points?

Originally Posted by zully32

Locate the absolute extrema of the function on the closed interval: f(x)= cos PIx on [1/2 , 4/3]



I will be very greatful if someone helped me understand what i must do

You should know that relative extrema occur at critical values. So let me ask you ... what are critical values and how does one find them?

Where else may absolute extrema exist on a closed interval?

Ok this going to take me a while because i am use to take math in spanish but ill manage to understand you ... anyway .....the end points are the points in which the graph ends ?

Originally Posted by zully32

Ok this going to take me a while because i am use to take math in spanish but ill manage to understand you ... anyway .....the end points are the points in which the graph ends ?

Yes. What is the value of the function at each of the endpoints?

[1/2,4/3]

What is the value of the function at each of the endpoints?

Originally Posted by zully32

[1/2,4/3]

no, the function values at the endpoints are and