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Confirm that the given function satisfies a differential equation.

Question in the attactment ! Please help me guys ! :(

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Quote:

Originally Posted by

**Lownavin** Question in the attactment ! Please help me guys ! :(

This is quite straightforward, differentiate the function twice, then substitute them into the DE to show that it is zero...

Re: Urgent ! Calculus test tml ! Help me please :(

Quote:

Originally Posted by

**Lownavin** Question in the attactment ! Please help me guys ! :(

$\displaystyle \frac{dy}{dx}=e^{5x}+5xe^{5x}$

$\displaystyle \frac{d^{2}y}{dx^2}=5e^{5x}+5e^{5x}+25xe^{5x}=10e^ {5x}+25xe^{5x}$

Re: Urgent ! Calculus test tml ! Help me please :(

How do i get 10e^5x to become 10dy/dx

Re: Urgent ! Calculus test tml ! Help me please :(

Quote:

Originally Posted by

**Lownavin** How do i get 10e^5x to become 10dy/dx

As has been said already, you substitute the derivatives into the differential equation. And you have been given the derivatives! Now it's your turn to do some work.

Show what you have tried and where you are stuck.