n --> infinity, limit root(n-1) - root(n) = zero ?

**nappysnake** · December 5th 2011, 01:01 PM

the result of the above mentioned limit is infinity minus infinity = zero, or do you calculate it differently?

**wnvl** · December 5th 2011, 01:07 PM

$\lim_{n \to \infty }\sqrt{n}-\sqrt{n-1}=\lim_{n \to \infty }(\sqrt{n}-\sqrt{n-1})\cdot \frac{\sqrt{n}+\sqrt{n-1}}{\sqrt{n}+\sqrt{n-1}}=\lim_{n \to \infty }\frac{1}{\sqrt{n}+\sqrt{n-1}}=0$

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n --> infinity, limit root(n-1) - root(n) = zero ?

Re: n --> infinity, limit root(n-1) - root(n) = zero ?

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