Results 1 to 2 of 2

Math Help - n --> infinity, limit root(n-1) - root(n) = zero ?

  1. #1
    Junior Member
    Joined
    Nov 2011
    From
    Vienna
    Posts
    45
    Thanks
    1

    n --> infinity, limit root(n-1) - root(n) = zero ?

    the result of the above mentioned limit is infinity minus infinity = zero, or do you calculate it differently?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Oct 2011
    From
    Belgium
    Posts
    36

    Re: n --> infinity, limit root(n-1) - root(n) = zero ?

    \lim_{n \to \infty }\sqrt{n}-\sqrt{n-1}=\lim_{n \to \infty }(\sqrt{n}-\sqrt{n-1})\cdot \frac{\sqrt{n}+\sqrt{n-1}}{\sqrt{n}+\sqrt{n-1}}=\lim_{n \to \infty }\frac{1}{\sqrt{n}+\sqrt{n-1}}=0
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. x -> infinity a root?
    Posted in the Algebra Forum
    Replies: 3
    Last Post: October 7th 2011, 12:50 PM
  2. square root + cube root of a number
    Posted in the Algebra Forum
    Replies: 2
    Last Post: December 5th 2010, 10:35 AM
  3. Replies: 2
    Last Post: April 6th 2009, 03:51 AM
  4. limit of xth root etc etc
    Posted in the Calculus Forum
    Replies: 11
    Last Post: May 18th 2008, 05:25 PM
  5. Replies: 1
    Last Post: March 29th 2008, 11:11 AM

Search Tags


/mathhelpforum @mathhelpforum