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**qwerty999** **a) Find all points in the interval [-1, 2] where the function f(x) = x^3 - x^2 satisfies**

the conclusion of the Mean Value Theorem.

I don't get it...i get to the point where i get 3x^2 - 2x = 2 , then i don't know how to get x

3x^2 - 2x - 2 = 0 , use the quadratic formula

b) f(x) = ln(x + 1) with domain [0; 3].

i got abs maximum as f(3) = ln4 and abs minimum as f(0)=ln1 ..lemme know if that is correct.

why don't you sketch the graph of the function over the given interval and check it yourself?

c)

Find all points in the interval [-1, 2] where the function f(x) = x^3 - x^2 satisfies the conclusion of the Mean Value Theorem.

thanks

(a) and (c) are the same problem