R'(x) = 6x^(-1/6) Find revenue when 300 units are produced and sold. I used intergls and got 834.83, but I am not so sure about my answer.. thanks
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i assume R'(x) is your marginal revenue function the Total revenue function[R(x)] is then You know that R(0) = 0 and hence c = 0 so R(300) = 579.75
question... when yuo do x^5/6 shouldnt it be 6*(6/5)x^(5/6), since you multiple by the reciprocal
If R(0) = 0 , then R(300) = 834.83
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