R'(x) = 6x^(-1/6)
Find revenue when 300 units are produced and sold.
I used intergls and got 834.83, but I am not so sure about my answer.. thanks
i assume R'(x) is your marginal revenue function
the Total revenue function[R(x)] is then $\displaystyle \int 6x^{\frac{-1}{6}} + c = 6 \cdot \frac{5}{6}x^{\frac{5}{6}} +c = 5x^{\frac{5}{6}} +c$
You know that R(0) = 0 and hence c = 0
so $\displaystyle R(x) = 5x^{\frac{5}{6}}$
R(300) = 579.75