1. ## Marginal Revenue Problem

R'(x) = 6x^(-1/6)
Find revenue when 300 units are produced and sold.

I used intergls and got 834.83, but I am not so sure about my answer.. thanks

2. ## Re: Marginal Revenue Problem

i assume R'(x) is your marginal revenue function

the Total revenue function[R(x)] is then $\displaystyle \int 6x^{\frac{-1}{6}} + c = 6 \cdot \frac{5}{6}x^{\frac{5}{6}} +c = 5x^{\frac{5}{6}} +c$

You know that R(0) = 0 and hence c = 0

so $\displaystyle R(x) = 5x^{\frac{5}{6}}$

R(300) = 579.75

3. ## Re: Marginal Revenue Problem

question... when yuo do x^5/6 shouldnt it be
6*(6/5)x^(5/6), since you multiple by the reciprocal

4. ## Re: Marginal Revenue Problem

$\displaystyle \int 6x^{-1/6} \, dx = \frac{36x^{5/6}}{5} + C$

If R(0) = 0 , then R(300) = 834.83