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Math Help - Marginal Revenue Problem

  1. #1
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    Marginal Revenue Problem

    R'(x) = 6x^(-1/6)
    Find revenue when 300 units are produced and sold.


    I used intergls and got 834.83, but I am not so sure about my answer.. thanks
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  2. #2
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    Re: Marginal Revenue Problem

    i assume R'(x) is your marginal revenue function

    the Total revenue function[R(x)] is then \int 6x^{\frac{-1}{6}} + c = 6 \cdot \frac{5}{6}x^{\frac{5}{6}} +c = 5x^{\frac{5}{6}} +c

    You know that R(0) = 0 and hence c = 0

    so R(x) = 5x^{\frac{5}{6}}

    R(300) = 579.75
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  3. #3
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    Re: Marginal Revenue Problem

    question... when yuo do x^5/6 shouldnt it be
    6*(6/5)x^(5/6), since you multiple by the reciprocal
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  4. #4
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    Re: Marginal Revenue Problem

    \int 6x^{-1/6} \, dx = \frac{36x^{5/6}}{5} + C

    If R(0) = 0 , then R(300) = 834.83
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