, which gives the indeterminate form
. Using l'Hospital' rule gives:
![\lim_{x \to \0}[\frac{4}{7}(3+x)^{-\frac{3}{7}} - \frac{4}{7}(3+x)^{-\frac{3}{7}}] = 0](http://latex.codecogs.com/png.latex?\lim_{x \to \0}[\frac{4}{7}(3+x)^{-\frac{3}{7}} - \frac{4}{7}(3+x)^{-\frac{3}{7}}] = 0)
But, the book gives a different answer and I confirmed their answer by using a different method. What I want to know exactly is why l'Hospital's rule failed to work for this limit.
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But, the book gives a different answer and I confirmed their answer by using a different method. What I want to know exactly is why l'Hospital's rule failed to work for this limit.
The derivative ofQuote:
Originally Posted by Pupil
But, the book gives a different answer and I confirmed their answer by using a different method. What I want to know exactly is why l'Hospital's rule failed to work for this limit.
is
.