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Math Help - Please Check My Work...

  1. #1
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    Please Check My Work...

    Freehand no Calcs: Equation of the Tangent Line.
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  2. #2
    MHF Contributor
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    Your m = 5ln(5) is correct, and your equation of the tangent line is correct also.

    I found m in another way:

    d/dx a^u = ln(a) *a^u *du/dx

    So, y = 5^(-1/x)
    y' = ln(5) *5^(-1/x) * (1/(x^2))
    At point (-1,5),
    y' = ln(5) *5^(-1 / -1) *(1 / (-1)^2)
    y' = ln(5) *5^1 *1/1
    y' = 5ln(5) --------------which is m also.
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