# Integration by parts problem

• Dec 1st 2011, 11:45 AM
LJDMDC5
Integration by parts problem
Can anyone help me solve this? I don't even know where to start.

http://latex.codecogs.com/gif.latex?...ln(n))}{n^2}dn
• Dec 1st 2011, 11:57 AM
wnvl
Re: Integration by parts problem
integrate by parts u=ln(n) ; v=-1/n
• Dec 2nd 2011, 05:01 PM
awkward
Re: Integration by parts problem
You might start with a substitution: $u = \ln x$.