Can anyone help me solve this? I don't even know where to start.

http://latex.codecogs.com/gif.latex?...ln(n))}{n^2}dn

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- Dec 1st 2011, 10:45 AMLJDMDC5Integration by parts problem
Can anyone help me solve this? I don't even know where to start.

http://latex.codecogs.com/gif.latex?...ln(n))}{n^2}dn - Dec 1st 2011, 10:57 AMwnvlRe: Integration by parts problem
integrate by parts u=ln(n) ; v=-1/n

- Dec 2nd 2011, 04:01 PMawkwardRe: Integration by parts problem
You might start with a substitution: $\displaystyle u = \ln x$.