differential equation

**emterics90** · February 19th 2006, 04:45 AM

$m_{t+h}-m_{t}=hm_t$ ,

so $\frac{dm_t}{dt}=m_t$

I am told that you use differential equations to the get the differentiation above, but I don't see how. Can anybody see?

**CaptainBlack** · February 19th 2006, 06:48 AM

Originally Posted by emterics90

$m_{t+h}-m_{t}=hm_t$ ,

so $\frac{dm_t}{dt}=m_t$

I am told that you use differential equations to the get the differentiation above, but I don't see how. Can anybody see?

I will rewrite this as

$<br /> m(t+h)-m(t)=hm(t)<br />$ ,

so:

$\frac{dm}{dt}=m(t)$

So you are looking for a function which is its own derivative, so
something like:

$m(t)=Ae^t$

should do.

RonL

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