$\displaystyle m_{t+h}-m_{t}=hm_t$,
so $\displaystyle \frac{dm_t}{dt}=m_t$
I am told that you use differential equations to the get the differentiation above, but I don't see how. Can anybody see?
I will rewrite this asOriginally Posted by emterics90
$\displaystyle
m(t+h)-m(t)=hm(t)
$,
so:
$\displaystyle \frac{dm}{dt}=m(t)$
So you are looking for a function which is its own derivative, so
something like:
$\displaystyle m(t)=Ae^t$
should do.
RonL