# Thread: find x coordinate of extrema

1. ## find x coordinate of extrema

Hey everyone.

problem: x^3-13x^2-10x+1
derivative: 3x^2-26x-10

I know you set it to zero, which ends up being (26+-(796)^1/2)/6

what do you do next?

2. ## Re: find x coordinate of extrema

You are done, you have two x values for extrema,

$x = \frac{26+\sqrt{796}}{6}, \frac{26-\sqrt{796}}{6}$

3. ## Re: find x coordinate of extrema

oh wow... I didnt realize it was that easy.

Thank you.