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Math Help - find x coordinate of extrema

  1. #1
    Junior Member
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    find x coordinate of extrema

    Hey everyone.

    problem: x^3-13x^2-10x+1
    derivative: 3x^2-26x-10

    I know you set it to zero, which ends up being (26+-(796)^1/2)/6

    what do you do next?
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  2. #2
    Master Of Puppets
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    Re: find x coordinate of extrema

    You are done, you have two x values for extrema,

    x = \frac{26+\sqrt{796}}{6}, \frac{26-\sqrt{796}}{6}
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  3. #3
    Junior Member
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    Re: find x coordinate of extrema

    oh wow... I didnt realize it was that easy.

    Thank you.
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