Hey everyone. problem: x^3-13x^2-10x+1 derivative: 3x^2-26x-10 I know you set it to zero, which ends up being (26+-(796)^1/2)/6 what do you do next?
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You are done, you have two x values for extrema, $\displaystyle x = \frac{26+\sqrt{796}}{6}, \frac{26-\sqrt{796}}{6}$
oh wow... I didnt realize it was that easy. Thank you.
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